{"content":{"sharePage":{"page":0,"digests":[{"id":"29257277","dateCreated":"1288293370","smartDate":"Oct 28, 2010","userCreated":{"username":"rmmankel","url":"https:\/\/www.wikispaces.com\/user\/view\/rmmankel","imageUrl":"https:\/\/www.wikispaces.com\/user\/pic\/1256861191\/rmmankel-lg.jpg"},"monitored":false,"locked":true,"links":{"self":"https:\/\/msmankel.wikispaces.com\/share\/view\/29257277"},"dateDigested":1532725966,"startDate":null,"sharedType":"discussion","title":"Complementary & Supplementary Angles","description":"Answer the questions from Online Assignment #3.","replyPages":[{"page":0,"digests":[{"id":"29405169","body":"My angle is sixty two and. my degrees is one hundred eighty. the supplement is one hundred eighteen.I know this because is one hundred eighty minus sixty two equal one hundred eighteen.","dateCreated":"1288622726","smartDate":"Nov 1, 2010","userCreated":{"username":"yosehanivaldez","url":"https:\/\/www.wikispaces.com\/user\/view\/yosehanivaldez","imageUrl":"https:\/\/www.wikispaces.com\/user\/pic\/1287599813\/yosehanivaldez-lg.jpg"}},{"id":"29405407","body":"there are right angles oh the book, papel.
\n
\nthere are straight angles on table street.","dateCreated":"1288622947","smartDate":"Nov 1, 2010","userCreated":{"username":"yosehanivaldez","url":"https:\/\/www.wikispaces.com\/user\/view\/yosehanivaldez","imageUrl":"https:\/\/www.wikispaces.com\/user\/pic\/1287599813\/yosehanivaldez-lg.jpg"}},{"id":"29425841","body":"My angles is 43 degrees.
\nThe complement is 47 degrees.
\nI know this because ninety minus forty three equals fourti seven.
\n
\n2 My angles is 43 degrees.
\nThe supplement is 137 degrees.
\nI know this because 180 minus forty three equals one hundred thirty-seven.
\n
\n3 Real world examples.
\n1)roof 180.
\n2)stairs 90.","dateCreated":"1288641164","smartDate":"Nov 1, 2010","userCreated":{"username":"maximorodriguez","url":"https:\/\/www.wikispaces.com\/user\/view\/maximorodriguez","imageUrl":"https:\/\/ssl.wikicdn.com\/i\/user_none_lg.jpg"}},{"id":"29435713","body":"1) My angle is sixty-one degrees and the camplementary is thirty-nine because ninety minus sixty-one is equal thirty -nine.
\n
\n2)my angle is sixty-one degrees the supplementary ia one-hundred nineteen because ano-hunred eighty minus sixty-one is equal one-hundred nineteen.
\n
\n3) A right anges is equql ninety.
\nA straight angles is equal one-hundred eighty","dateCreated":"1288650985","smartDate":"Nov 1, 2010","userCreated":{"username":"theangel95","url":"https:\/\/www.wikispaces.com\/user\/view\/theangel95","imageUrl":"https:\/\/www.wikispaces.com\/user\/pic\/1288647337\/theangel95-lg.jpg"}},{"id":"29437891","body":"My angle is 28 degrees.
\nThe complement is 62 degrees.
\nI know this because,I subter ninety by twenty eight is equale to sixty two.
\nMy angle is 28 degrees.
\nThe supplement is One hundred fifty two degrees.
\nI know this because, subtrace One-eighty by twenty-eight is equale to one hundred fifty-two.
\nThere are right angles on box.
\nThere are straight angles on rope.","dateCreated":"1288653420","smartDate":"Nov 1, 2010","userCreated":{"username":"deddeh.reeves","url":"https:\/\/www.wikispaces.com\/user\/view\/deddeh.reeves","imageUrl":"https:\/\/ssl.wikicdn.com\/i\/user_none_lg.jpg"}},{"id":"29437983","body":"1) My angle is twenty-four degrees.
\n The complement is sixty-six degrees.
\n I know this because if you subtract ninety & twenty-four the answer will be sixty-six which is the complement angle.
\n
\n2) My angle is twenty-four degrees.
\n The supplementary is one-hundred and fifty-six degrees.
\n I know this because if you subtract one-hundred and eighty by twenty-four the answer will be one-hundred and fifty-six which is the supplementary angle.
\n
\n3) There are right angles in the tail of a plane.
\n There are straight angles on the surface of a football field.
\n
\nMy current grade is A-","dateCreated":"1288653510","smartDate":"Nov 1, 2010","userCreated":{"username":"john.ortega","url":"https:\/\/www.wikispaces.com\/user\/view\/john.ortega","imageUrl":"https:\/\/ssl.wikicdn.com\/i\/user_none_lg.jpg"}},{"id":"29439865","body":"My angle is is fifty-six degrees.
\nIs acute.And is thirty-four degress
\nand complementary.I Know because
\ncomplementary is ninety ,so ninety degress minus
\nfifty-six degress is equals thirty-four degress.
\n
\nMy angle is fifty-six degress.
\nis acute.And is one hundred twenty four degress
\nand is suplementary.I Know because
\none hundred eighty degress minus fifty-six
\ndegress is equals one hundred twenty four degress.
\n
\n(My current grade is B+)","dateCreated":"1288655391","smartDate":"Nov 1, 2010","userCreated":{"username":"jessicabarreto1","url":"https:\/\/www.wikispaces.com\/user\/view\/jessicabarreto1","imageUrl":"https:\/\/www.wikispaces.com\/user\/pic\/1287104664\/jessicabarreto1-lg.jpg"}},{"id":"29490415","body":"my angle is fifty degress.The complement is forty degress.I know this because ninety minus fifty equals forty.","dateCreated":"1288722366","smartDate":"Nov 2, 2010","userCreated":{"username":"richardkendy","url":"https:\/\/www.wikispaces.com\/user\/view\/richardkendy","imageUrl":"https:\/\/ssl.wikicdn.com\/i\/user_none_lg.jpg"}},{"id":"29490739","body":"my angle is fifty degrees the supplement is one hundred thirty degrees. i know this because one eighty minus fifty is one thirty.","dateCreated":"1288722681","smartDate":"Nov 2, 2010","userCreated":{"username":"richardkendy","url":"https:\/\/www.wikispaces.com\/user\/view\/richardkendy","imageUrl":"https:\/\/ssl.wikicdn.com\/i\/user_none_lg.jpg"}},{"id":"29491033","body":"there are right angles on a tv screen and straight angles on a closet.","dateCreated":"1288722951","smartDate":"Nov 2, 2010","userCreated":{"username":"richardkendy","url":"https:\/\/www.wikispaces.com\/user\/view\/richardkendy","imageUrl":"https:\/\/ssl.wikicdn.com\/i\/user_none_lg.jpg"}},{"id":"29499341","body":"My angle is 53 degrees
\nThe complement is 37 degrees.
\nI know this because the complementary is 90 degrees so 90 degrees minus 53 equals 37 degrees.
\n
\nMy angle is 53 degrees
\nthe suplement is 127 degrees
\nI know this becaus the suplementary is 180 degrees so 180 degrees minus 53 equals 127 degrees.
\n
\nthere right angles on the book.
\nthere are straight angles on the ruler.","dateCreated":"1288730423","smartDate":"Nov 2, 2010","userCreated":{"username":"mondency","url":"https:\/\/www.wikispaces.com\/user\/view\/mondency","imageUrl":"https:\/\/ssl.wikicdn.com\/i\/user_none_lg.jpg"}},{"id":"29522371","body":"AGAIN. shaushuahsas
\nmy world exaples is.for right angles
\nis for me like a folder,and for straight
\nangles for me is like a ruler.!
\n
\nBye miss.","dateCreated":"1288749113","smartDate":"Nov 2, 2010","userCreated":{"username":"jessicabarreto1","url":"https:\/\/www.wikispaces.com\/user\/view\/jessicabarreto1","imageUrl":"https:\/\/www.wikispaces.com\/user\/pic\/1287104664\/jessicabarreto1-lg.jpg"}}],"more":27}]},{"id":"28614055","dateCreated":"1287365536","smartDate":"Oct 17, 2010","userCreated":{"username":"rmmankel","url":"https:\/\/www.wikispaces.com\/user\/view\/rmmankel","imageUrl":"https:\/\/www.wikispaces.com\/user\/pic\/1256861191\/rmmankel-lg.jpg"},"monitored":false,"locked":true,"links":{"self":"https:\/\/msmankel.wikispaces.com\/share\/view\/28614055"},"dateDigested":1532725967,"startDate":null,"sharedType":"discussion","title":"Pythagorean Theorem","description":"1) Write directions to find the hypotenuse (c) in your first triangle.
\n
\n2) Write directions to find the missing leg in your second triangle.
\n
\n*Only use words (no numbers or symbols).
\nUse first, second, third, etc.
\n<\/strong>*Write in complete sentences (start with a capital letter and end with a period).","replyPages":[{"page":0,"digests":[{"id":"28940889","body":"A-)
\nFirst, I write the Pythagorean Theorem a square plus b square equal c square.
\n
\nSecond, substitute a by eight square plus thirteen square equal c square and solve.
\n
\nThrid, sixty-four plus one hundred sixty-nine equal c square. After that add sixty-four and one hundred-nine equal c square.
\n
\nFourth, two hundred thirty-three square root equal c square root.
\n
\nFinally, fifteen point twenty-seven is equal to c, a is equal to eight, b is equal to thirteen and also c is equal fifteen point twenty-seven.","dateCreated":"1287793534","smartDate":"Oct 22, 2010","userCreated":{"username":"delacruzgenny","url":"https:\/\/www.wikispaces.com\/user\/view\/delacruzgenny","imageUrl":"https:\/\/www.wikispaces.com\/user\/pic\/1286829999\/delacruzgenny-lg.jpg"}},{"id":"28941563","body":"B-)
\nFirst, I write the Pythagorean Theorem a square plus b square equal c square.
\n
\nSecond, substitute "a" by eight square plus "b" square equal "c" by twenty-one square and solve.
\n
\nThrid, sixty-four plus "b" square equal four hundred forty-one. After that subtract negative sixty-four in both side.
\n
\nFourth, "b" square root equal three hundred seventy-seven square root.
\n
\nFinally, "b" square root is equal to nineteen point fourty-two, a is equal to eight, "b" is equal to nineteen point fourty-two and also "c" is equal twenty-one.","dateCreated":"1287794889","smartDate":"Oct 22, 2010","userCreated":{"username":"delacruzgenny","url":"https:\/\/www.wikispaces.com\/user\/view\/delacruzgenny","imageUrl":"https:\/\/www.wikispaces.com\/user\/pic\/1286829999\/delacruzgenny-lg.jpg"}},{"id":"28942099","body":"1) First, I write the formula of the Pythagorean Theorem to find my missing hypotenuse for my first triangle the formula is A square plus B square equal C square. Second, I substitute A square and B square for Three square plus six square equal C square. Then I find the answer of Three square and Six square whichis Nine plus Thirty six equal C squre. Third, I add both numbers and my answer is Forty Five equal C square then I find the square root of forty five which is Six point Seventy. My final answer is C equals
\nSix point Seventy.
\n
\n2) First, I write the formula of the Pythagorean Theorem to find the missing leg for my second triangle. Second, I write the formula A square plus B square equal C square. Then I substitute A square plus B square equal C square that is Six square plus B square equal fourteen square. Third, now I look for the answer of Six square and fourteen square which is Thirty six plus B square equal one hundred and ninety six. Fourth, now I put minus thirty six under positive thirty six and I cancel both numbers. Next, I put minus thirty six under positive one hundred and ninety six and then I substract both numbers and my answer is B square equal one hundred and sixty.Fifth, next I look for the square root oy onehundred snd sixty which is twelve point sixty five. My final answer is B equal twelve point sixty five.","dateCreated":"1287795920","smartDate":"Oct 22, 2010","userCreated":{"username":"john.ortega","url":"https:\/\/www.wikispaces.com\/user\/view\/john.ortega","imageUrl":"https:\/\/ssl.wikicdn.com\/i\/user_none_lg.jpg"}},{"id":"29036837","body":"I first put the formula A plus B equal C squares
\nand then put the numbers that going together to
\nformula,than are 5squared plus B squared equal
\nC squared.Then A will 25,B squared and C get 361
\nand then i subtract the number 25 to negative
\nand the rest with the number 361 the total will be 336 and then i do that with the squared root the total will be B equal 18.33","dateCreated":"1288034444","smartDate":"Oct 25, 2010","userCreated":{"username":"luisvelasquez","url":"https:\/\/www.wikispaces.com\/user\/view\/luisvelasquez","imageUrl":"https:\/\/ssl.wikicdn.com\/i\/user_none_lg.jpg"}},{"id":"29063171","body":"1)In my first triangle,i use the formula:c square equals six square plus twelve square.Then i calculate six square which gives thirty six plus twelve square whichgivesone hundred fourty four.c square equals thirty six plus one hundred fourty four.c square equals one hundred eighty.Then i calculate square root of one hundred eighty to find c. C equals thirteen point fourty one. (second) Inmy second triangle,i put my formula:a square plus b square equals c square and then i subtitute a and c with their values, seven and nineteen. Then i got seven square plus b square epuals nineteen square. seven square equals fourty nine and nineteen square equals three hundred sixty one. Then b square equals three hundred sixty one minus fourty nine. b square epuals square root of three hundred twelve. i calculate square root of three hundred twelve. b equals seventeen point sixty six.","dateCreated":"1288056267","smartDate":"Oct 25, 2010","userCreated":{"username":"christelle3","url":"https:\/\/www.wikispaces.com\/user\/view\/christelle3","imageUrl":"https:\/\/ssl.wikicdn.com\/i\/user_none_lg.jpg"}},{"id":"29075769","body":"1- I write the pythagorean theorem,second i put the formula A square + b square equal c square then i multiply a and b square, equal c squre then i add a+b equal c square and then i get the square root of the number equal to C","dateCreated":"1288092134","smartDate":"Oct 26, 2010","userCreated":{"username":"eltapo","url":"https:\/\/www.wikispaces.com\/user\/view\/eltapo","imageUrl":"https:\/\/ssl.wikicdn.com\/i\/user_none_lg.jpg"}},{"id":"29119875","body":"1 formula a square a square b is difference in
\nsquare c is b seven square plus teen c
\n
\n2 two hundred five square c square tree siting fourteng square a in b esquare point trirti one
\n
\n3 finalli b esquare root is esquare to nineteen point fourty two is square to eiht
\nb is square the fourty two","dateCreated":"1288129623","smartDate":"Oct 26, 2010","userCreated":{"username":"luigy20_","url":"https:\/\/www.wikispaces.com\/user\/view\/luigy20_","imageUrl":"https:\/\/ssl.wikicdn.com\/i\/user_none_lg.jpg"}},{"id":"29151299","body":"1) I write the pythagorean theorem.
\n2)I subtitud the letter for the number, four for a and eigth for b.
\n3) I solved four squere is equal sixteen and eight squere is equal sixty four.
\n4)I add sixteen and sixty four, its equal eighty.
\n5)Then i took the squere root of eighty and the answer was c squere is eight point ninety five.","dateCreated":"1288178480","smartDate":"Oct 27, 2010","userCreated":{"username":"la_lady_26","url":"https:\/\/www.wikispaces.com\/user\/view\/la_lady_26","imageUrl":"https:\/\/ssl.wikicdn.com\/i\/user_none_lg.jpg"}},{"id":"29151435","body":"1) I write the pythagorean theorem.
\n2)I subtitud the letter for the number, six for a squere and fifteen for b squere.
\n3) I solve six squere is equal thirty six and fefteen squere is equal two hundred twenty five.
\n4)Isubtract thrity six of the both sidas and b squere is the same, and when i subtract two hundred twenty five minus thrity six i get one hundred eighty nine.
\n5) then i took the squere root of one hundred eighty nine and the answer was thirteen point seventy four.","dateCreated":"1288179089","smartDate":"Oct 27, 2010","userCreated":{"username":"la_lady_26","url":"https:\/\/www.wikispaces.com\/user\/view\/la_lady_26","imageUrl":"https:\/\/ssl.wikicdn.com\/i\/user_none_lg.jpg"}},{"id":"29201895","body":"First,I use the pythagorean formula,Where the letter A sqare plus B sguare equal to C square.Second,I substitute four for the letter A square and five for the litter B square and then I sove the four square which equal to sixteen plue five square which equal to twentyfive.At the end sixteen plue twentyfive is equale to fourtyone equal to C square,I cross cancel the square root on both said to the equation and fourtyone equal to C.And my answer is six point fourty.The second part.First,I wrote the formula B square equal to C aquare minus A square.Second,I substitute the number four for the lettle A square and the number fifteen for the lettre C square.Than,I sove my equation.B square equal fifteen square minus four squaer and the is two hundred and nine equal B and my answer is fourteen point fourtyfive.","dateCreated":"1288221602","smartDate":"Oct 27, 2010","userCreated":{"username":"deddeh.reeves","url":"https:\/\/www.wikispaces.com\/user\/view\/deddeh.reeves","imageUrl":"https:\/\/ssl.wikicdn.com\/i\/user_none_lg.jpg"}},{"id":"29434417","body":"1.i put a square plus b square equal c square.segund eigth square plus ten square equal c square.third sixten four plus one hundred equal c square.forth i put c square root equal one hundred sixten four equal twelve.2.first a square plus b square equal c square. segund eigh square plus b square equal twenty one square.third sixten fourplus b square equal four hundred foury one.i put b square root equal three hundred seventen seven equal nineth point four.
\n1. first i take the formula. segund seven square plus eleven square equal c square. third i put fourty nine plus one hundred one equal c square.fourth i put c square root equal square one hundred seventh equal thirth.
\n2. first i take the formula. segund senven square plus b square equal twinty square.third i put fourty nine plus b square equal four hundred.c square equal root three hundred one.c equal eigten point seven.","dateCreated":"1288649730","smartDate":"Nov 1, 2010","userCreated":{"username":"armandaandrade5","url":"https:\/\/www.wikispaces.com\/user\/view\/armandaandrade5","imageUrl":"https:\/\/ssl.wikicdn.com\/i\/user_none_lg.jpg"}},{"id":"29849729","body":"asquare plus b square is equal to to c square
\n
\ni substitute de a square for two and c square for nineteen
\n
\ni solve seven squared. It equals forty-nine. Then i solve fifteen. It equals two hundred twenty-five.
\n
\ni added forty- nine to two hundred twenty-five.
\n
\nI equals two hundred seventy-four.
\n i take the square root of two hundred seventy-four.
\n
\nThe answer is sixteen point fifty-five","dateCreated":"1289255678","smartDate":"Nov 8, 2010","userCreated":{"username":"sanders.volcy1","url":"https:\/\/www.wikispaces.com\/user\/view\/sanders.volcy1","imageUrl":"https:\/\/ssl.wikicdn.com\/i\/user_none_lg.jpg"}}],"more":32}]},{"id":"28300449","dateCreated":"1286842985","smartDate":"Oct 11, 2010","userCreated":{"username":"deddeh.reeves","url":"https:\/\/www.wikispaces.com\/user\/view\/deddeh.reeves","imageUrl":"https:\/\/ssl.wikicdn.com\/i\/user_none_lg.jpg"},"monitored":false,"locked":true,"links":{"self":"https:\/\/msmankel.wikispaces.com\/share\/view\/28300449"},"dateDigested":1532725969,"startDate":null,"sharedType":"discussion","title":" About the mcas","description":" Yes i took the mcas,and I think the mcas is great. It will help me to improves on my acadimic grades. I found out that some of my grades are low.I need to focus more on my Maths. Because I find maths too tough for me, I'm going to consider every option or
\nresources avaible for me to used.
\nDeddeh Reeves","replyPages":[{"page":0,"digests":[{"id":"28331999","body":" IS Very important WHAT HAPPENS IF IT IS BETTER BUT STILL ENFUENSES You will need to TE.","dateCreated":"1286898561","smartDate":"Oct 12, 2010","userCreated":{"username":"yosehanivaldez","url":"https:\/\/www.wikispaces.com\/user\/view\/yosehanivaldez","imageUrl":"https:\/\/www.wikispaces.com\/user\/pic\/1287599813\/yosehanivaldez-lg.jpg"}}],"more":0}]},{"id":"28080955","dateCreated":"1286396707","smartDate":"Oct 6, 2010","userCreated":{"username":"rmmankel","url":"https:\/\/www.wikispaces.com\/user\/view\/rmmankel","imageUrl":"https:\/\/www.wikispaces.com\/user\/pic\/1256861191\/rmmankel-lg.jpg"},"monitored":false,"locked":true,"links":{"self":"https:\/\/msmankel.wikispaces.com\/share\/view\/28080955"},"dateDigested":1532725969,"startDate":null,"sharedType":"discussion","title":"Midpoints, Endpoints, and Distance","description":"Directions: Write in complete sentences and use details.
\n
\n1) Write two endpoints. Each endpoint should have one positive number and one negative number.
\n
\n2)Find the midpoint of your two endpoints. Explain in words how you found the answer.
\n
\n3) Think about how to find an endpoint. How is this similar or different than finding a midpoint?","replyPages":[{"page":0,"digests":[{"id":"28287417","body":"(-2,4) (-4,2)
\nx1+x2\/2=
\n-2+-4\/2=
\n-6\/2=
\n-3
\n
\ny1+y2\/2=
\n4+2\/2=
\n6\/2=
\n3
\n Midpoint: (-3,3)
\nI wrote the formula first, then I changed every term for each right number example x1=-2
\nthen I added -2 and -4 that is equal to -6 then i divided by 2 that is equal to -3 then I did the same process to find Y
\n
\nTo find one endponit is kind of different but not too much we just need to write the formula y change each tern with the number that you alreaddy have. then seeing the formula you do the process.","dateCreated":"1286827145","smartDate":"Oct 11, 2010","userCreated":{"username":"Jotapeguero","url":"https:\/\/www.wikispaces.com\/user\/view\/Jotapeguero","imageUrl":"https:\/\/www.wikispaces.com\/user\/pic\/1286827780\/Jotapeguero-lg.jpg"}},{"id":"28309353","body":"The difference is that one has the two end points and the other must be found","dateCreated":"1286854755","smartDate":"Oct 11, 2010","userCreated":{"username":"maximorodriguez","url":"https:\/\/www.wikispaces.com\/user\/view\/maximorodriguez","imageUrl":"https:\/\/ssl.wikicdn.com\/i\/user_none_lg.jpg"}},{"id":"28331907","body":"midpoints ex:To calculate the distance d of a line segment with endpoints (x1, y1) and (x2, y2) use the FORMULA","dateCreated":"1286898473","smartDate":"Oct 12, 2010","userCreated":{"username":"yosehanivaldez","url":"https:\/\/www.wikispaces.com\/user\/view\/yosehanivaldez","imageUrl":"https:\/\/www.wikispaces.com\/user\/pic\/1287599813\/yosehanivaldez-lg.jpg"}},{"id":"28384671","body":" 1)(-7;2)(9;-2)
\nend (end) mid
\n7-2 ?? 9-2
\nx1+x2\\2equal y1y2\\2equal2
\n-7+x2\\2equal9 2+y2\\2equal-2
\n 7x2equal18 -2+y2equal-4
\nx2equal25 y2equal-6
\n
\n2)[-7;2] [9;-2]
\nthe midpoint is x1+x2 devide
\n
\n by 2 then y1+y2
\nthen the answer is 7+9 devide by2 equal8.5
\nthe other is2+_2devided by2 equal 0 the endpoint was a little different because if you use the same formula then you replace x1 by it"s number =x2 devided by 2 then the same for y then you find the endpoint.","dateCreated":"1286969659","smartDate":"Oct 13, 2010","userCreated":{"username":"Tania.Nelson","url":"https:\/\/www.wikispaces.com\/user\/view\/Tania.Nelson","imageUrl":"https:\/\/ssl.wikicdn.com\/i\/user_none_lg.jpg"}},{"id":"28509355","body":"I make the formula for to find de midpoint.
\nendpoints. (5,-9)and(-17,3)
\n X1+X2=\/2 X1+X2=\/2
\n 5+-17=\/2 -9+3=\/2
\n -12\/2 -6\/2
\n Midpoint (-6,-3).
\n
\nI did the formula and make according to the formula
\ntells.the beginnig is the formula X1+X2=\/2 and after
\ni subtitute de X and Y for the endpoints that in this case is
\n(5,-9)and(-17,3),after i did the accounts and take
\nthe anserws and divide per 2 and I have the endpoint.!
\nthe disferent between mid point and end point is the formula,
\nbecause de mid point is X1+X2=\/2 everytime i rebember the song :D)
\nand of the end point is X1+x=X2\/2 this is similiar and the different i don't Know ,I forgot.!","dateCreated":"1287104114","smartDate":"Oct 14, 2010","userCreated":{"username":"jessicabarreto1","url":"https:\/\/www.wikispaces.com\/user\/view\/jessicabarreto1","imageUrl":"https:\/\/www.wikispaces.com\/user\/pic\/1287104664\/jessicabarreto1-lg.jpg"}},{"id":"28724775","body":"j(_4,2) f(5,_2)
\n_4+5%*(0.5)midpoits
\n
\n2+_2%2*(0)midpoints
\nI make the formula x1+x2%2. and thats I can found the answer.","dateCreated":"1287519778","smartDate":"Oct 19, 2010","userCreated":{"username":"emelyalvarez92","url":"https:\/\/www.wikispaces.com\/user\/view\/emelyalvarez92","imageUrl":"https:\/\/ssl.wikicdn.com\/i\/user_none_lg.jpg"}},{"id":"28759497","body":"A(_4,2) B(5,_2)
\nX1+X2%2 Y1+Y2%2
\n_4+5%2 2+_2%2=
\n(0.5,O)Midpoint
\nI use the formula x1+x2%2, y1+y2%.. and than I subtitute this formula for number, and I add and then I divide. I make the answer doing this formula.","dateCreated":"1287573200","smartDate":"Oct 20, 2010","userCreated":{"username":"emelyalvarez92","url":"https:\/\/www.wikispaces.com\/user\/view\/emelyalvarez92","imageUrl":"https:\/\/ssl.wikicdn.com\/i\/user_none_lg.jpg"}},{"id":"28759701","body":"To find the endpoint you have to use the formula x1+y2%2, x2+y252. And then subtitute, you need to multiply 2 all time..
\nThe midpoint and endpoint are so diference because in midpont you don't have to multiply just divide. I think there are two diference pasos to solve midpoint and endpoint","dateCreated":"1287573766","smartDate":"Oct 20, 2010","userCreated":{"username":"emelyalvarez92","url":"https:\/\/www.wikispaces.com\/user\/view\/emelyalvarez92","imageUrl":"https:\/\/ssl.wikicdn.com\/i\/user_none_lg.jpg"}},{"id":"28786721","body":"a(-4,4)w(-2,2)
\nx1+X2 Y1+Y2
\n _
\n 2 2
\n-4+2 -4+2
\n=-3 =
\n 2 2
\nmidpoint (-3,-1)
\n
\n
\nexplain i got the answer adding and dividing by 2 I use the furmular of the proces","dateCreated":"1287598846","smartDate":"Oct 20, 2010","userCreated":{"username":"yosehanivaldez","url":"https:\/\/www.wikispaces.com\/user\/view\/yosehanivaldez","imageUrl":"https:\/\/www.wikispaces.com\/user\/pic\/1287599813\/yosehanivaldez-lg.jpg"}},{"id":"28811647","body":"x2,y2
\n(6,4) and (-2,8)
\nx1+x2 divide by 2
\ny1+y2 divide by 2
\nx1+6 divide by 2, 2 times -2
\nx1+6 equal 4
\nx1=-10
\n
\ny1+4 divide by 2, eight times 2
\ny1+4 equal 16
\ny1= 12
\n
\n